. (10 points - bonus problem) the fredholm alternative states that: if b ? r m is not in the column space of am×n, then it is not orthogonal to the left nullspace of a. equivalently, using matrix language, we have that either the system ax = b or the system at y = 0 with y t b = 1 has a solution. verify the fredholm alternative for the system ax = b with a = ? ? 1 2 3 4 5 6 7 8 9 ? ? and b = (0, 1, 1). (hint: if ax = b does not have a solution show that at y = 0 with y t b = 1 has a solution).
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Category: art | Author: Sagi Boris
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